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(2-3x)^2=4x(x-2)
We move all terms to the left:
(2-3x)^2-(4x(x-2))=0
We add all the numbers together, and all the variables
(-3x+2)^2-(4x(x-2))=0
We calculate terms in parentheses: -(4x(x-2)), so:We get rid of parentheses
4x(x-2)
We multiply parentheses
4x^2-8x
Back to the equation:
-(4x^2-8x)
-4x^2+(-3x+2)^2+8x=0
We add all the numbers together, and all the variables
-4x^2+8x+(-3x+2)^2=0
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